(1.25)^x+3=(0.8)^1-2x

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Solution for (1.25)^x+3=(0.8)^1-2x equation: 



(1.25)^x+3=(0.8)^1-2x

We move all terms to the left:

(1.25)^x+3-((0.8)^1-2x)=0



We calculate terms in parentheses: -((0.8)^1-2x), so:

(0.8)^1-2x

determiningTheFunctionDomain
-2x+(0.8)^1

We add all the numbers together, and all the variables

-2x+0.8

Back to the equation:

-(-2x+0.8)



We get rid of parentheses

(1.25)^x+2x-0.8+3=0

We add all the numbers together, and all the variables

2x+(1.25)^x+2.2=0

We move all terms containing x to the left, all other terms to the right

2x+(1.25)^x=-2.2

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